Question

Find the values of y for which the distance between the points P(2,-3) and Q(10,y) is 10 units. *

(-9,3)

(-3,9)

(-9,-3)

(-3,-9)

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Answer 1

Answer:

√(-3-2)^2+(y-10)^2=10

√(-5)^2+(y-10)^2=10

√25+y^2-100=10

y^2-100=10-25

y^2=-15-100

y^2=-90

y= -30