Question

find the values of y for which the distance
between the points P(2,-3) and Q(10,y) is 10 units
​

Answer 1

Answer:

Step-by-step explanation:

P(2,-3) and Q(10,y)

√(10-2)²+(y+3)²=10

squaring both sides

64+y²+6y+9=10

Or,y²+6y-27=0

Or,y²+9y-3y-27=0

Or,(y+9)(y-3)=0

y=-9 y=3