Question

Find the values of y for which the distance between the points P( 2 , – 5 ) and Q ( 10 , y ) is 10 units.​

Answer 1

Step-by-step explanation:

Distance between two point (x1,y1) and (x2,y2) is given by,

=(x2−x1)2+(y2−y1)2

102=(10−2)2+(y+3)2

(y+3)2=102−82

(y+3)2=62

y+3=±6

∴y=3ory=−9

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Answer 2

Answer:

Step-by-step explanation:

HEY MATE!

HERE IS YOUR ANSWER!

⇒Thank you so much for asking this question.

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Given:-

Distance = 10 units

x₁ = 2     x₂ = 10

y₁ = -5    y₂ = x

To find

y₂

The distance between two points P&Q is

$\sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2} } = 10 \\\\ \sqrt{(10 - 2)^{2} + (y _2+ 5) ^{2} } = 10 \\\\ {8}^{2} + (y_2 + 5) ^{2} = {(10)}^{2} \\\\\\ 64 + (y_2+ 5) ^{2} = 100 \\\\\\ (y _2+ 5) ^{2} = 36 \\\\\\ (y _2+ 5) = \sqrt{36} \\\\ (y _2+ 5) = 6 \\ \\y_2 = 1$

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