find the values of your for which the distance between the points P (2,-3) Q (10,y) is 10 units.
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Answer:
y=3 or -9
Step-by-step explanation:
given:P(2,-3),Q(10,y) and PQ=10 units. therefore PQ² =100 by using distance formula , we have: (10-2)² +(y+3)² =100 therefore 64 +(y+3)² = 100. (y+3)²=36 (y+3)=+-6 y+3=6 or y+3=-6. therefore y=3 or -9
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