Question

Find the values of z that satisfy the quadratic equation -12z^2-96z=144

Answer 1

Answer:

$- 12 {z}^{2} - 96z - 144 = 0 \\ - 12( {z }^{2} + 8z + 12) = 0 \\ = {z}^{2} + 8z + 12 = 0 \\ {z}^{2} + 6z + 2z + 12 = 0 \\ z(z + 6) + 2(z + 6) = 0 \\ (z + 2)(z + 6 ) \\ z = - 2 \: or \: z = \: - 6$