Question

Find the Values
quadratic equation , Kx (x - 2) +6 = 0

so that they have two equal
roots​

Answer 1

Answer:

please Mark as brilliant answer

Answer 2

Here Is Your Answer Mate.....;

kx(x – 2) + 6 = 0

or kx^2 – 2kx + 6 = 0

Comparing the given equation with ax^2 + bx + c = 0, we get

a = k, b = – 2k and c = 6

We know, Discriminant = b^2 – 4ac

= ( – 2k)^2 – 4 (k) (6)

= 4k^2 – 24k

For equal roots, we know,

b^2 – 4ac = 0

4k^2 – 24k = 0

4k (k – 6) = 0

Either 4k = 0 or k = 6 = 0

k = 0 or k = 6

However, if k = 0, then the equation will not have the terms ‘x^2‘ and ‘x‘.

Therefore, if this equation has two equal roots, k should be 6 only

Hope it's Helpful.....:)