Find the values
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a=30,b=30,c=90...............
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Step-by-step explanation:
In ∆ABC
a+60°+50°=180°
a+110°=180°
a=180°-110°
a=70°
In ∆AED
c+60°+30°=180°
c+90°=180°
c=180°-90°
c=90°
let angle c be x
x+a=180°
x+70°=180°
x=180°-70°
x=110°
In ∆CDF
b+110°+30°=180°
b+140°=180°
b=180°-140°
b=40°
hope this helps you
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