find the valve of sin 30°cos 60°- tan²45°
Answers
Answered by
0
Answer:
We the value of tan(45^{0}) = 1, \ sin(30^{0}) = \frac{1}{2}, \ cos(60^{0}) = \frac{1}{2}tan(45
0
)=1, sin(30
0
)=
2
1
, cos(60
0
)=
2
1
\begin{gathered}\frac{tan(45^{0})}{sin(30^{0}) + cos(60^{0})}\\\\= \frac{1}{\frac{1}{2} + \frac{1}{2}}\\\\= \frac{1}{1}\\\\= 1\end{gathered}
sin(30
0
)+cos(60
0
)
tan(45
0
)
=
2
1
+
2
1
1
=
1
1
=1
Hence, the value of \frac{tan(45^{0})}{sin(30^{0}) + cos(60^{0})}
sin(30
0
)+cos(60
0
)
tan(45
0
)
Step-by-step explanation:
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Answered by
1
Answer:
-3/4
Step-by-step explanation:
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