Math, asked by valikagill, 4 months ago

Find the variance and standard deviation for the following data 65,68,58,44,48,45,60,62,60,50​

Answers

Answered by sanjaychauhan7778
0

Answer:

hlo idbon't have kno w the answersh

Answered by Simrankaur1025
3

Given:

Length of Rectangle = 40 cm

Breadth of rectangle = 10 cm

\sf Area_{\;(square)} = Area_{\;(rectangle)}Area

(square)

=Area

(rectangle)

⠀⠀

To find:

Perimeter of square?

⠀⠀━━━━━━━━━━━━━━━━━━━━━

☯ Let side of square be x cm.

⠀⠀⠀

\begin{gathered}\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}\\ \\\end{gathered}

★Accordingtothequestion:

\sf Area_{\;(square)} = Area_{\;(rectangle)}Area

(square)

=Area

(rectangle)

⠀⠀

We know that,

⠀⠀

\sf Area_{\;(square)} = (side)^2Area

(square)

=(side)

2

\sf Area_{\;(Rectangle)} = length \times breadthArea

(Rectangle)

=length×breadth

⠀⠀

Therefore,

⠀⠀

\begin{gathered}:\implies\sf side \times side = length \times breadth\\ \\\end{gathered}

:⟹side×side=length×breadth

\begin{gathered}:\implies\sf x \times x = 40 \times 10\\ \\\end{gathered}

:⟹x×x=40×10

\begin{gathered}:\implies\sf x^2 = 400\\ \\\end{gathered}

:⟹x

2

=400

\begin{gathered}:\implies\sf \sqrt{x^2} = \sqrt{400}\qquad\quad\bigg\lgroup\bf Squaring\;both\;sides \bigg\rgroup\\ \\\end{gathered}

:⟹

x

2

=

400

Squaringbothsides

\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{x = 20}}}}}\;\bigstar\\ \\\end{gathered}

:⟹

x=20

\therefore\;{\underline{\sf{Side\;of\;square\;is\;{\textsf{\textbf{20\;cm}}}.}}}∴

Sideofsquareis20cm.

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Now, Finding Perimeter of square,

⠀⠀

\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}

Asweknowthat,

\begin{gathered}\star\;{\boxed{\sf{\pink{Perimeter_{\;(square)} = 4 \times side}}}}\\ \\\end{gathered}

Perimeter

(square)

=4×side

\begin{gathered}:\implies\sf Perimeter_{\;(square)} = 4 \times 20\\ \\\end{gathered}

:⟹Perimeter

(square)

=4×20

\begin{gathered}:\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(square)} = 80\;cm}}}}}\;\bigstar\\ \\\end{gathered}

:⟹

Perimeter

(square)

=80cm

\therefore\;{\underline{\sf{Perimeter\;of\;square\;is\;{\textsf{\textbf{80\;cm}}}.}}}∴

Perimeterofsquareis80cm.

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\begin{gathered}\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:Formulas\:related\:to\:it\:\bigstar}}}} \\ \\\end{gathered}

★Formulasrelatedtoit★

\begin{gathered}\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Area\ formula&\bf Perimeter\ formula\\\cline{1-3}\sf Square&\tt side \times side}&\tt 4 \times side\\\cline{1-3}\sf Rectangle&\tt length \times breadth&\tt 2(length + breadth)\\\cline{1-3}\sf Triangle&\tt \dfrac{1}{2} \times base \times height&\tt sum\of\ all\ sides\ of\ \triangle\\\cline{1-3}\end{array}\end{gathered}

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