Question

find the variance of n natural number?

Answer 1

Step-by-step explanation:

Variance of first n natural numbers={(1²+2²+3²+…+n²)/n}-(Mean)²

={(n+1)(2n+1)/6}-{(n+1)²/4}

=(n+1)/12{4n+2–3(n+1)}

=(n+1)(n-1)/12

=(n²-1)/12

hope it's very helpful for u dude....