Question

find the variance of n natural numbers
​

Answer 1

Answer:

Given an integer N, the task is to find the variance of the first N natural numbers.

Step-by-step explanation:

Therefore, Variance = ((1 – 3)2 + (2 – 3)2 + (3 – 3)2+(4 – 3)2+(5 – 3)2) / 5 = (4 + 1 + 0 + 1 + 4) / 5 = 10 / 5.

Answer 2

Answer:

Hii, Here is your answer :

Step-by-step explanation:

Variance=

n

∑n

2

−(

n

∑n

)

2

=

6n

n(n+1)(2n+1)

−(

2n

n(n+1)

)

2

=(n+1)[

6

2n+1

−

4

(n+1)

]

=

12

(n+1)

[4n+2−3n−3]

=

12

(n+1)

×(n−1).

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