find the vaue of tan^2ø -sec^2ø
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3
Answer:
it should be sec²-tan²=1
Answered by
0
Answer:
-1
Step-by-step explanation:
tan²∅ - sec²∅
taking minus as common
= - (- tan²∅ + sec²∅)
= -(sec²∅-tan²∅)
= -(1) as we know that [sec²θ - tan²θ= 1]
= -1
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