find the vaule of (x/y)² if (4/9)‐³×(2/3)‐2=(x/y)
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(9/4)³ × (3/2)² = (y/x)^8
(3/2)^6 × (3/2)² = (y/x)^8
(3/2)^8 = (y/x)^8
y/x = 3/2
x/y = 2/3
(x/y)² = 4/9
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