Question

Find the +ve value of k if the quadratic equation 3x2-k√3x+4=0 has real roots

Answer 1

Here is your answer
a = 3
b = -k√3
c = 4

If quadratic equation has real roots than
${b}^{2} - 4ac = 0 \\ ( - k \sqrt{3} ) {}^{2} - 4 \times 3 \times 4 = 0 \\ 3 {k}^{2} - 48 = 0 \\ 3 {k}^{2} = 48 \\ {k}^{2} = \frac{48}{3} \\ {k}^{2} = 16 \\ k = \sqrt{16} \\ k = 4 \: \: and \: - 4$

Therefore the positive value of k is 4

Hope it helps you

Answer 2

Answer:

the roots are real and not equal so b²-4ac is greater than equal to 0