Question

find the vector AB and its magnitude if it has initial point A (1, 2, - 1) and final. B( 3, 2, 2)​

Answer 1

Answer:

Explanation:

A= i+2j-k(initial)

B=3i+2j+2k(final)

AB=final-initial

AB=3i+2j+2k-i-2j+k

AB=2i+3k ANS

|AB|=√2²+3³

|AB|=√13 ANS

Answer 2

Given:

initial point A (1, 2, - 1) and final point B( 3, 2, 2)​

To Find:

vector AB and its magnitude

Solution:

A (1, 2, - 1)

B( 3, 2, 2)​

Writing in vector form

A = i+2j-k

B = 3i+2j+2k

now,

vector AB = B - A

AB = 3i+2j+2k-i-2j+k

AB = 2i+3k

also,

|AB| = $\sqrt{2^{2}+3^{2} }$

|AB| = $\sqrt{4+9$

|AB| = $\sqrt{13}$

So, vector AB =  2i+3k and its magnitude is  $\sqrt{13}$.