Question

find the vector and cartesian equation of the plane passing through the points (1,2,3)
and parallel to the lines $\frac{x+1}{2} =\frac{y+2}{-1} =\frac{z+3}{3} and \frac{x-2}{1} =\frac{y+1}{2} =\frac{z+2}{2}$

Answer 1

Answer:

ANSWER

r→=i^+2j^−4k^+λ(2i^+3j^+6k^)

r→=i^−3j^+5k^+μ(i^+j^−k^) are equations of given lines

Vector equation of a plane passing through a point c and parallel to vectors a→ and b→ is r→=c+ta→+sb→

i.e  r→=(i^+2j^=4k^)+t(2i^+3j^+6k^)+s(i^+j^−k^)

Cartesian form of given lines are

2x−1 = 

Step-by-step explanation:

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