Question

find the vector and scalor product and angle of two vectors A=2i+3j-5k and B=3i+j-2k also find magnitude of vector A and B
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Answer 1

Answer:

scalor product=19

Explanation:

a.b=a1a2+b1b2+c1c2

= 2×3+3×1+(-5)(-2)

= 6+3+10

=19

for angle,

cos= a.b/mod A × mod B

cos angle=19/root 494