Physics, asked by angadshinde9732, 5 months ago

Find the vector drown for the points (-4, 10, 7) to the point (3,-2,1). Also find its
magnitude.​

Answers

Answered by nirman95
19

To find:

The vector drawn for the points (-4, 10, 7) to the point (3,-2,1) and its magnitude.

Calculation:

The vector joining the following points

  • (-4 , 10 , 7)

  • (3 , -2 , 1 )

will be :

\therefore\: \vec{r} =  \{3 - ( - 4) \}( \hat{i}) +  \{ - 2 - 10 \}( \hat{j}) +  \{1 - 7 \} ( \hat{k})

 =  >  \vec{r} =  \{3 + 4 \}( \hat{i}) +  \{ - 12 \}( \hat{j}) +  \{ - 6\} ( \hat{k})

 =  >  \vec{r} =  \{7\}( \hat{i}) +  \{ - 12 \}( \hat{j}) +  \{ - 6\} ( \hat{k})

  \boxed{=  >  \vec{r} = 7( \hat{i}) - 12( \hat{j})  - 6( \hat{k})}

So, magnitude of the vector :

 \therefore \:  | \vec{r}|  =  \sqrt{ {7}^{2}  +  {( - 12)}^{2} +  {( - 6)}^{2}  }

 =  > \:  | \vec{r}|  =  \sqrt{ 49 +  144 +  36  }

 =  > \:  | \vec{r}|  =  \sqrt{ 229 }

 \boxed{ =  > \:  | \vec{r}|  = 15.13 \: units}

Hope It Helps.

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