Math, asked by vipinsuresh, 9 months ago

find the vector equation of a line passing through the point having position vectors 5i^+4j^+3k^ and having direction ratios -3,4,2.

Answers

Answered by knjroopa

Step-by-step explanation:

Given find the vector equation of a line passing through the point having position vectors 5i^+4j^+3k^ and having direction ratios -3,4,2.

Let vector p be the position vector of the point 5i + 4j + 3k and vector q be the vector parallel to the line and the direction ratios are – 3,4,2
Now vector p = 5i + 4j + 3k
Also vector q = -3i + 4j + 2k
The vector equation of a line passing through a point with position vector p and parallel to q is r = p + λq
Therefore vector equation of the required line will be
Vector r = (5i + 4j + 3k) + λ(- 3i + 4j + 2k)

Reference link will be

https://brainly.in/question/16739649

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