Find the vector equation of the line passing through the point 2i + 3j + k and parallel to the vector 4i -2j + 3k.
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Answer:Find the vector equation of the line which is parallel to the vector 2i-j-3k and ... Now as r is the position vector of P(x, y, z), we get xi + yj + zk=(5+2%)i-(2+%).j+(4+3%)k. ... The given line passes through the point (1, -2, 5) and is parallel to the vector ... vector equation of the line is F =i-2.j +5k+x(2i +3.j-k) where \ is a parameter
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