Physics, asked by 6352096590, 6 months ago

Find the vector of p = 2i+3j-k with x-axis

Answers

Answered by yash21212121

0

Answer:

2i^...... because the vector along the x axis is i^.

Answered by sureshshiva

0

Answer:

Cosα=x/r

Cosα=2/√(4+9+16)

α=cos^-1(2/√29)

=68.19859051°

=68.2° (approx).

Hope this helps.

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