find the vector which has magnitude of 10 unit ans it's direction is parallel to the vector 12i-5j
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Answer:
120i-50j/13
Step-by-step explanation:
First we need to find a unit vector of the given vector
∴Magnitude = √[12² + (-5)²] = 13
Now Unit vector = Given vector/Magnitude
∴Unit vector = (12i-5j)/13
∵Unit vector has magnitude 1 and is parallel to given vector
∴Vector parallel to 12i-5j having magnitude 10 will be = (12i-5j)/13 × 10
= (120i-50j)/13
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