Question

find the vectors xi-3j+5kand 2xi-xj-k are perpendicular to each other find x plz answer fast important​

Answer 1

Two vectors are perpendicular:

then x×2x+(-3)(-x)+5×(-1) = 0

2x²+3x-5 = 0

2x²+5x-2x-5 = 0

x(2x+5)-1(2x+5) = 0

(x-1) and (2x+5) = 0

x= 1,-5/2

then the value of x is 1,-5/2

Answer 2

Answer:

1,-5/2

Step-by-step explanation:

let a=xi-3j+5k , b=2xi-xj-k

since it is given that ab are perpendicular a.b=0

(xi-3j+5k)(2xi-xj-k)=0

2x^2+3x-5=0

2x^2+5x-2x-5=0

x(2x+5)-1(2x+5)=0

(x-1)(2x+5)=0

x=1,x=-5/2