find the velocity and time taken to reach the ground for a body dropped from a tower of height 10m
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For example, the square root of 1.02 s^2 equals 1.01 s. Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.
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Answer:
here is the answer
using
v^2-u^2=2as
then
v=√2×10×10
v=√200
v=10√2
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