Physics, asked by shiny049, 7 months ago

find the velocity having magnitude 15 and parallel to 3icap+2jcap-6kcap​

Answers

Answered by Anonymous
4

\huge\mathfrak\blue{Answer:}

Given:

  • We have been given a vector
  • \sf{\vec{r} = 3 \hat{i} + 2 \hat{j} - 6 \hat{k}}

To Find:

  • We have to find a velocity vector having magnitude 15 and parallel to given vector

Concept Used:

A Quantity having both magnitude as well as direction is known as a vector quantity

\boxed{\sf{\red{\vec{A} = |A| \times \hat{A}}}}

Where

  • \sf{|A|} = Magnitude of A vector \\
  • \sf{\hat{A}} = Unit vector of A which the represent the direction of vector

Assuming a general vector A which is given below :

\sf{\vec{A} = a \hat{i} + b \hat{j} + c \hat{k}}

Then the magnitude of given A vector is calculated by the formula

\boxed{\sf{|A| = \sqrt{(a)^2 + (b)^2 + (c)^2}}}

\\

Solution:

We have been given a vector :

\sf{\vec{r} = 3 \hat{i} + 2 \hat{j} - 6 \hat{k}}

\\

\underline{\large\mathfrak\purple{Magnitude \: of \: Vector \: r \: is}}

\implies \sf{| \: r \: | = \sqrt{(3)^2 + (2)^2 + (-6)^2}}

\implies \sf{| \: r \: | = \sqrt{9 + 4 + 36}}

\implies \sf{| \: r \: | = \sqrt{49}}

\implies \boxed{\sf{| \: r \: | = 7}}

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Finding the unit vector in direction of given r vector

\implies \boxed{\sf{\hat{r} = \dfrac{\vec{r}}{|r|}}}

\implies \sf{\hat{r} = \left ( \dfrac{3 \hat{i} + 2 \hat{j} - 6 \hat{k}}{7} \right ) }

Unit vector in direction of r vector is

 \boxed{\sf{\hat{r} = \left ( \dfrac{3 \hat{i} + 2 \hat{j} - 6 \hat{k}}{7} \right ) }}

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\underline{\large\mathfrak\purple{Finding \: value \: of \: velocity \: vector:}}

Magnitude = 15

Parallel to given vector i.e.

Unit vector of v = Unit vector of r

\implies \sf{\vec{v} = |v| \times \hat{v}}

\implies \sf{\vec{v} = 15 \times \hat{r}}

\implies \sf{\vec{v} = 15 \times \left ( \dfrac{3 \hat{i} + 2 \hat{j} - 6 \hat{k}}{7} \right )}

\implies \sf{\vec{v} = \dfrac{15}{7} \times (3 \hat{i} + 2 \hat{j} - 6 \hat{k} ) }

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\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}

\large\boxed{\sf{\red{Velocity = \dfrac{15}{7} \: (3 \hat{i} + 2 \hat{j} - 6 \hat{k} )}}}

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