find the velocity of a bullet fired in standard air if this Mach angle is 30 degree take y = 1.5
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Answer:
Given : Mach angle α=30˚
R = 287 J/kg k
K = 1.4
Temperature t = 15˚ c
= 15 + 273 = 288˚ k
Now, Velocity of sound = KRT−−−−−√
=1.4×287×288−−−−−−−−−−−−√
c = 340.17 m/s
Now, Mach angle,
Sin α=c/v
i.e. Sin 30˚=340.17V
∴ V = 680.34 m/s
∴ The velocity of a bullet fired in standard air is 680.34 m/s
Step-by-step explanation:
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