Find the velocity of a bullet of mass 10g which is fired from a pistol of
mass 1.5kg. The recoil velocity of the pistol is 2.5 m/s.
Answers
Answered by
2
Answer:
Conservation of linear momentum gives,
m1v1+m2v2=0
m1v1=−m2v2
v1=m1−m2v2
Given, m1=10g=(100010)kg,
m2=1 kg,
v2=−5m/s
∴v1=10/1000+1×5
or v1=500m/s.
Answered by
1
Momentum of the gun = momentum of the bullet (law of conservation of momentum)
M = 1.5 kg
m = 10 g = 0.01 kg
v = ?
V = 2.5 m/s = recoil velocity
(M) x V = m x v
(1.5) x 2.5 = 0.01 x v
v = 375 m/s
:-)
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