Question

Find the velocity of a bullet of mass 10g which is fired from a pistol of

mass 1.5kg. The recoil velocity of the pistol is 2.5 m/s. Also pls tell that the recoil velocity will remain positive or we will change it to negative. The one coming with the most accurate answer and explanation will be marked as the brainliest. Pls help !!!!​

Answer 1

Explanation:

Let the direction in which the bullet is fired be positive.

Therefore,

Mass of Bullet(m)=20 grams=0.02 kg

Mass of Pistol(M)=2 kg

Initial Velocity of Bullet(u)=0 m/s

Initial Velocity of Pistol(U)=0 m/s

Final Velocity of Bullet(v)=150 m/s

Final Velocity of Pistol(V)= Recoil Velocity of Bullet = ?

According to the Law of Conservation of Momentum,

mu + MU = mv + MV

(0.02)(0) + (2)(0) = (0.02)(150) + (2)(V)

0 + 0 = 3 + 2V

-3/2 = V

V = -1.5 m/s

Therefore, the recoil velocity of the pistol will be 1.5 m/s in the opposite direction.(As the sign is negative)

PLEASE MARK ME AS BRAINLIEST