Question

Find the velocity of a car which is stopped in 10 seconds by applying breaks. The retardation due to breaks in 2.5m/s

Answer 1

t = 10 s
a = 2.5 m/s2
v =0
than, from motion formula 
v = u + at
we have the value of u = 25 m/s

Answer 2

Given:-

• Final velocity,v= 0m/s
• Time taken to stop ,t = 10s
• Retardation ,a = -2.5m/s²

To Find:-

• Initial velocity ,u ?

Solution:-

According to the Question

It is given that a car which is stopped in 10 second by applying breaks and the reterdiation due to Break is 2.5m/s².

Using 1st equation of motion

• v = u + at

Where,

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken

Putting the value we get

→ 0 = u + (-2.5) × 10

→ -u = -25

→ u = 25m/s

• Hence, the initial velocity of the car is 25m/s²

$\: \: \: \: \: \:$$\huge\fbox{→25m/s²}$