Question

Find the velocity of a projectile at the highest point, if it is projected with a speed 15 m s
−1
, in the direction 45
o
above horizontal. [take g=10ms
−2
]​

Answer 1

Answer:

At highest point the final velocity will be 15×cos45=10.6

sec

m

in the horizontal direction (parallel to ground).

At highest point the y component of velocity becomes zero so only velocity in the horizontal direction remains