Find the velocity of a satellite which revolves in a circular orbit of radius 35000km and
completes one round in 11 hours.
pls answer fast
pls dont copy frm old answers coz this is not tht same Q
Answers
Answered by
1
Answer:
Here, h=1000 km=1000×10
3
m=10
6
m
r=R+h=6.38×10
6
+10
6
=7.38×10
6
m
Orbital speed,
v
0
=
R+h
GM
=
7.38×10
6
6.67×10
−11
×6×10
24
=7364m s
−1
Time period,
T=
v
0
2πr
=
7.364×10
3
2×(22/7)×(7.38×10
6
)
=6297s.
Answered by
0
Answer:
Applying the Formula of Orbital Velocity of a Satellite, we've
V = 2pi . R
T
Given that R = 35000 Km = 35,000,000 m and T = 11 hours = 39,600 sec
.: V = (2pi).(35,000,000 m)
(39,600)
V = 5,553 m/s
Hope it Helped!
Explanation:
where V = velocity of given satellite
R = Radius of satellite
T = period of oscillation of the satellite in question
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