Question

Find the velocity of block on reaching ground if released from rest as shown

Answer 1

V = u + at

dropped so u = 0 m/s

a = g ( acceleration due to gravity)

S = ut + (1/2)at²

h = (1/2)gt²   ( h - height from ground)

=> t² = 2h/g

=> t = √(2h/g)

v = u + at

=> v = 0 + g√(2h/g)

=> v = √(2hg)

velocity of block on reaching ground  =√(2hg)  m/s