Question

Find the velocity of bullet of mass 5 gram which is fired from a pistol of mass 1.5 kg. The recoil velocity of pistol is 1.5 m.s-1

Answer 1

Answer:

Answer is below

Explanation:

Given,

Mass of bullet, m1 = 5 gram = 0.005 kg

Mass of pistol, m2 = 1.5 kg

The velocity of a bullet, v1 = ?

Recoil velocity of pistol, v2 = 1.5 m.s-1

Using law of conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

Here, Initial velocity of the bullet, u1 = 0

Initial recoil velocity of a pistol, u2 = 0

∴ (0.005 kg)(0) + (1.5 kg)(0) = (0.005 kg)(v1) + (1.5 kg)(1.5 m.s-1)

0 = (0.005 kg)(v1)+(2.25 kg.m.s-1)

v1=-450 m.s-1

Hence, the recoil velocity of pistol is 450 m.s-1.