Question

find the velocity of escape at the moon given that it's radius is 1.7×1000000 m and the value of g at its surface is 1.63m/sec²

Answer 1

Hey Arjeet
your answer is here
escape velocity = square root of 2gR
so v^2 = 2x1.63x1.7x1000000
v = 235 m/sec

Hope it help you

Thanks

Be Brainly

Mark me as Brainliest

Answer 2

Answer:

• 2.354 × 10³ m/s

Explanation:

Given :

• Radius (R) = 1.7 × 10⁶ m.
• Acc. due to gravity (g) = 1.63 m/s²

To find :

• Escape velocity (Vₑ)

Formula used :

• Vₑ = √2gR

Solution :

=> Vₑ = √2 × (1.63) × (1.7 × 10⁶)

=> Vₑ = √3.26 × (1.7 × 10⁶)

=> Vₑ = √5.542 × 10⁶

=> Vₑ = 2.354 × 10³

∴ The escape velocity is 2.354 × 10³ m/s