Question

find the velocity of projection if a projectile is projected at an angle of 60 degree to achieve its maximum height of 375 m


plz guys help me fast!​

Answer 1

Answer :

• Velocity of projection is 100 m/s

Explanation :

• Angle of the projection (θ) = 60°
• Maximum Height (H) = 375 m

Use formula for Maximum Height in Projectile Motion :

$\longrightarrow \sf{H \: = \: \dfrac{u^2 \sin ^2 \theta}{2g}} \\ \\ \longrightarrow \sf{375 \: = \: \dfrac{u^2 \sin ^2 (60^{\circ})}{2 \: \times \: 10}} \\ \\</p><p>\longrightarrow \sf{375 \: = \: \dfrac{u^2 \: \times \: \bigg( \dfrac{\sqrt{3}}{2} \bigg) ^2 }{20}} \\ \\ \longrightarrow \sf{375 \: = \: \dfrac{u^2 \: \times \: \dfrac{3}{4}}{20}} \\ \\ \longrightarrow \sf{u^2 \: = \: \dfrac{375 \: \times \: 20 \: \times \: 4}{3}} \\ \\ \longrightarrow \sf{u^2 \: = \: \dfrac{7500 \: \times \: 4 }{3}} \\ \\ \longrightarrow \sf{u^2 \: = \: 2500 \: \times \: 4} \\ \\ \longrightarrow \sf{u^2 \: = \: 10000} \\ \\ \longrightarrow \sf{u \: = \: \sqrt{10000}} \\ \\ \longrightarrow \sf{u \: = \: 100} \\ \\ \underline{\underline{\sf{Velocity \: of \: Projection \: is \: 100 \: ms^{-1}}}}$

Answer 2

Explanation:

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$\bf \huge \: Question \: \:$

• Find the velocity of projection if a projectile is projected at an angle of 60 degree to achieve its maximum height of 375 m

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$\bf \huge \: Given \: \:$

• projectile is projected at an angle of 60 degree
• its maximum height of 375 m

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$\bf \huge \: To\: Find\:$

• The velocity of projection

Answer :

$\bf\: We \: Know \:$

$\sf{H \: = \: \dfrac{u^2 \sin ^2 \theta}{2g}} \\ \\ </p><p>\bf\red{ Putting \: the \: value } \: \:$

$\sf{375 \: = \: \dfrac{u^2 \sin ^2 (60^{\circ})}{2 \: \times \: 10}} \\ \\ \sf{375 \: = \: \dfrac{u^2 \: \times \: \bigg( \dfrac{\sqrt{3}}{2} \bigg) ^2 }{20}} \\ \\ \sf{375 \: = \: \dfrac{u^2 \: \times \: \dfrac{3}{4}}{20}} \\ \\ \sf{375 \: = \: \dfrac{u^2 \: \times \: 0.75}{20}} \\ \\ \sf{u^2 \: = \: \dfrac{375 \: \times \: 20}{0.75}} \\ \\ \sf{u^2 \: = \: \dfrac{7500}{0.75}} \\ \\ \sf{u^2 \: = \: 9333} \\ \\ \sf{u \: = \: \sqrt{9333}} \\ \\ \sf{u \: = \:96.6 }$

Hence Solved