Question

find the velocity of the escape at the moon given that its radius is 1.7×10⁶m and the value of g at its seface is 1.63ms-². the answer is. i)2.354× 10³ ms-¹ ii)2.000×10³ ms-¹ iii)23.54×10³ms-¹ iv)20.00×10ms-¹​

Answer 1

Answer:

• 2.354 × 10³ m/s

Explanation:

Given :

• Radius (R) = 1.7 × 10⁶ m.
• Acc. due to gravity (g) = 1.63 m/s²

To find :

• Escape velocity (Vₑ)

Formula used :

• Vₑ = √2gR

Solution :

=> Vₑ = √2 × (1.63) × (1.7 × 10⁶)

=> Vₑ = √3.26 × (1.7 × 10⁶)

=> Vₑ = √5.542 × 10⁶

=> Vₑ = 2.354 × 10³

∴ The escape velocity is 2.354 × 10³ m/s.