Question

Find the velocity of the particle for the time interval t = 5s to t= 10s from the given graph.​

Answer 1

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From the Question,

The object covers a distance of:

• 10m at 5 seconds

• 20m at 10 seconds

Thus, (x,y) = (5,10) and (x’,y’) = (10,20)

The expression for the velocity of the particle is given by:

$\boxed{\sf{v = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}}}$

Putting the values,we get:

$\sf{v = \frac{20 - 10}{10 - 5} } \\ \\ \implies \: \sf{v = \frac{10}{5}} \\ \\ \huge{ \implies \: \: \sf{v = 2ms {}^{ - 1}}}$

Thus,the velocity of the particle from t = 5s to t = 10s is 2m/s

Answer 2

Given:-

From the graph,

Particle travels 10m in first 5 seconds and 20m in 10 seconds

To find:-

Velocity of the particle in the time interval t=5 to t=10 sec

Explanation:-

From the graph

From t=5 to t=10 seconds

$\sf Displacement=20-10=10 m$

$\sf time=10-5=5 \: sec$

Now we know that

$\boxed{\sf Velocity=\dfrac{Displacement}{time}}$

substituting the values we got

$> v = \dfrac{10}{5}$

$\boxed{\sf Velocity=2ms^{-1}}$