Question

Find the velocity of transverse wave if a man of 20kg is suspended from one end of the string having per unit length 0.2kg/m​

Answer 1

Answer:

ANSWER

M = 2.50 kg

T = 200 N

l = 20.0 m

Mass per unit length, μ=M/l=2.50/20=0.125Kgm

−1

The velocity (v) of the transverse wave in the string is given by the relation:

v=

T/μ

=

200/0.125

=

1600

=40 m/s

∴ Time taken by the disturbance to reach the other end,

t=l/v=20/40=0.5s

Answer 2

Answer:

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