Question

Find the velocity with which A ball is thrown upward reaches maximum height in 5 seconds also find its maximum height

Answer 1

$\textbf{ \huge{ Hello Mate! }}$

Here, v = 0 [ at some point it will come to rest ]

t = 5 s

a = - 10 $m/s^2$ [ Since against gravity ]

Since,

v = u + at

0 = u + ( - 10 )( 5 )

50 m/s = u

And

${v}^{2} - {u}^{2} = 2as \\ {0}^{2} - {50}^{2} = 2( - 10)s \\ \frac{ - 2500}{ - 20} = s \\ 125 \: m = s$

$\textsf{\red{=> Initial velocity that ball had 50 m/s }}$

$\textsf{\red{=> Distance travelled by it is 125 m }}$

$\textbf{ Have great future ahead! }$

Answer 2

$\huge{Holla}$

Thanks for asking question

We know that Here, v = 0, and t = 5s we also know against the gravity a = -10 m/s²

Now, using the formula [ v = u + at ]

we get u = 50m / s

Then,

Applying [ v² - u² = 2as

=> 0 - 50² = 2× (-10)s

=> s = 2500/2

=> s = 125m

$\bold{I\:Hope\:its\:Help\:You}$