Question

FIND THE VELOCITY WITH WHICH A STONE FALLING FROM HEIGHT 50 m HITTED THE GROUND.

Answer 1

v^2-u^2=2gS.

Now let me explain the variables in the above equation. Here v is the final velocity(required answer), u is the initial velocity and is equal to 0 as it is dropped from a particular height initially at rest,g is the acceleration due to gravity and S is the distance covered(here it is equal to 90 m).

So here we have the values once again..

v -required answer.

u=0.

g=9.8 .

S=90.

Just put them in the equation and solve for v and you will get the answer to be 42 metres per second.

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Answer 2

ya this equation can be applied