Find the vertex angle of an isosceles triangle whose one of the base angle is 70°.
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in Δ ABC
∠ a = 70°
let the base angles be x
∴ x +x+70 = 180
2x + 70 = 180
2x= 180 - 70
2x = 110
x = 110\2
∴ x = 55
∴the base angles are 55°
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Answer:
the vertex angle is 40°
Step-by-step explanation:
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