Find the vertex of d of a parallelogram abcd whose three vertices are (3,-1) b (5,3) and c (0,3)
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Answer:
Let the fourth vertex D =(x,y)
We know that the diagonals of a parallelogram bisect each other. So,the
midpoint of AC is same as the mid point of BD.
Mid point of two points (x
1
,y
1
) and (x
2
,y
2
) is calculated by the formula (
2
x
1
+x
2
,
2
y
1
+y
2
)
So, midpoint of AC= Mid point of BD
=>(
2
−2+8
,
2
3+3
)=(
2
6+x
,
2
7+y
)
=>(
2
6
,
2
6
)=(
2
6+x
,
2
7+y
)
=>6+x=6;7+y=6
=>x=0;y=−1
Hence, D=(0,−1)
Step-by-step explanation:
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