Question

Find the vertex of the quadratic function: f(x)=x^2+10x+14
The equation for the vertex is:

X=-b/2a
y=f(-b/2a)
Pre calculus

Answer 1

Answer:

( - 5, - 11)

Step-by-step explanation:

f(x) = x² + 10x + 14

The coordinates for the vertex are:

$x = - \frac{b}{2a} = - \frac{10}{2} = - 5$

y = f( - 5) =( - 5)² + 10 × ( - 5) + 14 = - 11

( - 5, - 11)

Zeroes of given function are $x_{12}$ = - 5 ± √11