Find the vertex of the quadratic function: f(x)=x^2+10x+14
The equation for the vertex is:
X=-b/2a
y=f(-b/2a)
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Answer:
( - 5, - 11)
Step-by-step explanation:
f(x) = x² + 10x + 14
The coordinates for the vertex are:
y = f( - 5) =( - 5)² + 10 × ( - 5) + 14 = - 11
( - 5, - 11)
Zeroes of given function are = - 5 ± √11
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