Question

Find The Vertex Of Y²+6Y+2X=-7

Answer 1

Answer:

The required vertex is V(1,-3)

Explanation:

Given parabola is

$y^2+6y+2x=-7$

$y^2+6y=-2x-7$

To make the L.H.S as a perfect square, add 9 on both sides

$y^2+6y+9=-2x-7+9$

$(y+3)^2=-2x+2$

$(y+3)^2=-2(x-1)$

comparing this equation with open leftward parabola $(y-k)^2=-4a(x-h)$

we get (h,k)=(1,-3)

Therefore, the vertex is V(1,-3)