Question

Find the vertical asymptotes of $f( \rm x) = \cfrac{2x + 1}{ {x}^{2} - 2x - 8 }$​

Answer 1

Answer:

The answer is  $x-4=0$ and $x+2=0$

Step-by-step explanation:

Given function is:

     $f(x)=\dfrac{2x+1}{x^2-2x-8}=\dfrac{2x+1}{(x-4)(x+2)}$

Concept:

Vertical asymptotes of a rational function are all the lines of the form $x=c$ for which f(x) is not defined.

Hence for the given function vertical asymptotes are  $x-4=0$ and $x+2=0$