Question

Find the vertical component of a force of 50 N making
an angle of 30° with x-axis.​

Answer 1

ANSWER

60o |

60o | |

60o | | | Fy (the vert. comp.)

60o | | | Fy (the vert. comp.) ↑

60o | | | Fy (the vert. comp.) ↑← 30o |

60o | | | Fy (the vert. comp.) ↑← 30o | Fx (the horizontal componenet)

F = √(Fx2 + Fy2)

F = √(Fx2 + Fy2) Fy = 50 · cos 60o = 50 · (1/2) = 25 N

F = √(Fx2 + Fy2) Fy = 50 · cos 60o = 50 · (1/2) = 25 N Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N

F = √(Fx2 + Fy2) Fy = 50 · cos 60o = 50 · (1/2) = 25 N Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N I see, that vector sign did not appear in my comment above, so the vector equation is

F = √(Fx2 + Fy2) Fy = 50 · cos 60o = 50 · (1/2) = 25 N Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N I see, that vector sign did not appear in my comment above, so the vector equation is → → →

F = √(Fx2 + Fy2) Fy = 50 · cos 60o = 50 · (1/2) = 25 N Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N I see, that vector sign did not appear in my comment above, so the vector equation is → → → F = 50 cos 30o i + 50 cos 60o j

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