Find the vertice of the triangle x+y=10 , 2x+3y=5, 6x-y=11
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Answer:
(1.9, 0.4), (3, 7), (25, -15)
Step-by-step explanation:
Coordinates of the vertices of the triangle are solutions of systems of pairs of linear equations:
1). x + y = 10 and 2x + 3y = 5
2). x + y = 10 and 6x - y = 11
3). 2x + 3y = 5 and 6x - y = 11
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1). x + y = 10 ..... (1)
2x + 3y = 5 ..... (2)
(1)×2 - (2)
- y = 15 ⇒ y = - 15
x - 15 = 10 ⇒ x = 25
Coordinates of first vertex are (25, - 15)
2). x + y = 10 .... (1)
6x - y = 11 ..... (2)
(1) + (2)
7x = 21 ⇒ x = 3
3 + y = 10 ⇒ y = 7
Coordinates of second vertex are (3, 7)
3). 2x + 3y = 5 ..... (1)
6x - y = 11 ..... (2)
(2)×3 + (1)
20x = 38 ⇒ x = 1.9
11.4 - y = 11 ⇒ y = 0.4
Coordinates of third vertex are (1.9, 0.4)
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