Question

Find the vertices of a triangle, the mid points of whose sides are (3, 1), (5, 6) and (-3, 2).​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-3

now,

now,by elimination:

now,by elimination:x1 + x2 = 6

now,by elimination:x1 + x2 = 6x1 + x3 = -6

now,by elimination:x1 + x2 = 6x1 + x3 = -6-----------------

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +----------------

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7 of y3 in any of the equation we get:

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7 of y3 in any of the equation we get:y3 + y2 = 12

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7 of y3 in any of the equation we get:y3 + y2 = 12y2 = 12 - 7

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7 of y3 in any of the equation we get:y3 + y2 = 12y2 = 12 - 7y2 = 5

now,by elimination:x1 + x2 = 6x1 + x3 = -6------------------ - +---------------- x2 - x3 = 12(1)by elimination of (1) and x2 + x3 = 10 { from above }x2 - x3 = 12x2 +x3 = 10----------------2x2= 22x2= 11 { from above }y3 - y2 = 2y3 + y2 = 12-----------------2y3 = 14y3 = 7 of y3 in any of the equation we get:y3 + y2 = 12y2 = 12 - 7y2 = 5y1 = -3