find the vlaue of k if x-1 is the factor of p(x)=4x^3+3x^2-4x+k
Answers
Answered by
7
Answer:
k = -3
Step-by-step explanation:
P(x) = 4x³+3x²-4x+k
g(x) = x-1
∴ P(1) = 4(1)³+3(1)²-4(1)+k = 0
= 4+3-4+k = 0
= k = -3
Answered by
13
Solution :
The given polynomial is
p(x) = 4x³ + 3x² - 4x + k
Since (x - 1) is a factor of p(x),
p(1) = 0
⇒ 4 (1)³ + 3 (1)² - 4 (1) + k = 0
⇒ 4 + 3 - 4 + k = 0
⇒ k = - 3
Therefore, the value of k is (- 3)
••• Extra •••
Let's factorize the given polynomial with the value of k = - 3
Then, p(x) = 4x³ + 3x² - 4x - 3
= 4x³ - 4x + 3x² - 3
= 4x (x² - 1) + 3 (x² - 1)
= (x² - 1) (4x + 3)
= (x + 1) (x - 1) (4x + 3) ,
which is the factorization of the given polynomial p(x)
Cubingwitsk:
Awesome!
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